2021 CAP Virtual Congress / Congrès virtuel de l'ACP 2021

Search for the high-spin members of the α:2n:α band in 10Be

9 Jun 2021, 13:15

10m

Underline Conference System

Oral (Non-Student) / Orale (non-étudiant(e)) Nuclear Physics / Physique nucléaire (DNP-DPN) W2-6 Experimental Nuclear Physics I (DNP) / Physique nucléaire expérimentale I (DPN)

Speaker

Dr Sriteja Upadhyayula (TRIUMF)

Description

There is strong evidence that some states in ${}^{10}$Be exhibit a molecular-like $\alpha$:2n:$\alpha$ configuration. Based on theoretical studies, it appears that the $6.179$ MeV 0${}^{+}$ state in ${}^{10}$Be has a pronounced $\alpha$:2n:$\alpha$ configuration with an $\alpha$-$\alpha$ inter-distance of $3.55$ fm [Itagaki and Okabe, (2000)]. This is 1.8 times more than the corresponding value for the ${}^{10}$Be ground state. The 2${}^{+}$ at 7.542 MeV in ${}^{10}$Be is believed to be the next member of this rotational band. The state at 10.2 MeV was identified as a 4${}^{+}$ member in recent experiments. The algebraic model predicts that the terminating member of this band is the 6${}^{+}$ state that should be found around 13 MeV. We performed an experiment to search for the 6${}^{+}$ state in ${}^{10}$Be at around 13 MeV excitation energy in the excitation function for ${}^6$He+$\alpha$ scattering. Stringent limits on the properties of such a state have been established using Monte Carlo methods. The results of this study will be presented.